Okay, we're going to quickly hijack some of a response we made to a different thread with a related subject:
The Sylesti genetics are simple punnet square type, with N ('N' being the site's 'code letter' for 'nothing') being most dominant, and the rest of the alphabet following A-through-Z in descending order.
Let's use our Leihu and Gourami as an example pairing
 x 
As you can see, the only visible mutation between them is Leihu's Unicorn Tail (Tips)
Their genetics are as such :
Leihu:
gd1=BD
gd2=AB
gd3=AC
md1=FH
md2=NN
md3=NA
Gourami:
gd1=DF
gd2=BC
gd3=AB
md1=NG
md2=NE
md3=NA
gd1= BD x DF
BB, BF, DD, DF
(50% either Tiger or Marbled vis)
gd2= AB x BC
AB, AC, BC, BB
(50% either Wing Tips or Faded Tips vis)
gd3= AC x AB
AA, AB, AC, BC
(75% Frost Runes, 25% Tribal Runes vis)
md1= FH x NG
NF, NH, GH, FG
(50% no-vis (25% carried Unicorn Tail (Tips) 25% carried Snow Leopard Tail (Tiger)), (25% visible Unicorn Tail (Tips), 25% visible Snow Leopard Tail
md2= NN x NE
NN, NN, NE, NE
(50% no-vis, no-carry, 50% carried Jingle Bells)
md3= NA x NA
NN, NA, NA, AA
(75% no-vis (25% no-vis, no-carry, 50% carried Feathered Wings), 25% Feathered Wings vis)
In full relation to the question: if both parents have a carry, as in Leihu and Gourami's md3= NA x NA, there is a 25% chance for an offspring to inherit it visibly ('AA').
If the parents each have a carry, but the letters are different eg. md3= NA x NC, then if the offspring rolled the 25% chance then its genetics would be 'AC' (if you were after the 'C' being the visible trait, you'd have to have either two carried C's or a parent with C and a parent with a letter between D and Z.)
If only one parent has a carry, and the other has nothing at all eg. md2= NN x NE, then there is a 50% chance that the offspring will carry, but no chance for a visible in that generation. |
