Just a few questions about hiddens. How do they interact when breeding? If I breed a pet with a carried trait to a pet with the same trait hidden, will the hidden show itself, or the vis? What about breeding a vis to a hidden? Or do you need to breed a hidden to a hidden? I hope that makes sense. Also, some odds or percentages of the likelihood of a vis or carry would be nice to have. (Basically, I just still don't know how hiddens work. Breeding is complicated. XP)

It's all statistical. Perhaps an example?

You've got pet A that has mutation one as EF (E would be visible and F would be hidden)

You've got pet C that has mutation one as XF (F would be carried with no visible)

These are the outcomes from breeding A and C together:
XE
XF
EF
FF
(Approximately 25% each)

So in answer to your first question, breeding a pet with a hidden trait with a pet that has that same trait as a carried does not guarantee that the offspring will carry that trait (either as a carried, vis or hidden). That's not to say the hidden trait of A can't present itself as a visible, it just depends which of E or F A happens to contribute to that particular breeding.

Then you've got pet D that has mutation two as AE (A would be visible and E would be hidden)

You've also got pet F that has mutation two as EE (E would be visible)

These are the outcomes from breeding D and F together:
AE
EE
(Approximately 50%)

As F will always contribute E, you're always guaranteed to have E to show in the offspring (as a visible or hidden) but given that D will contribute A 50% of the time and E 50% of the time, you've got a 50 / 50 chance of E become visible.

Thheeeeennnn you've got pet G that has mutation three as AC (A would be visible and C would be hidden)

You've also got pet I that has mutation three as BC (B would be visible and C would be hidden)

These are the outcomes from breeding G and I together:
AB
AC
BC
CC
(Approximately 25%)

Both G and I have a 50 / 50 chance of contributing C but given that they both have the chance the chance of getting C somewhere in the offspring is higher (as a hidden again or a visible) but is not guaranteed as G has the chance to contribute A only and I has the chance to contribute B only.

I did think of one other permutation where there is no commonality between the traits:

You have pet J that has mutation three as AC (A would be visible and C would be hidden)

You also have pet L that has mutation three as BF (B would be visible and F would be hidden)

These are the outcomes from breeding J and L together:
AB
AF
BC
CF
(Approximately 25%)

If you were seeking the C hidden as a visible, the only way this could occur would be for pet L to contribute F which would hide under C. At the same time, you run the risk that J and L will both contribute A and B (their dominant traits) respectively which would leave you with neither hidden in the offspring. F can't become visible, it can only been a hidden as there is nothing in the "gene pool" it is dominant to.

Hopefully that makes things a little clearer? Let me know if I can clarify anything?


Edit: To tweak something.

Thank you, that does help a lot! The examples make it a lot easier for me to understand. (It's still a little complicated, but that's probably because I'm really bad at math. :P) I'll definitely be referring back to this!

You're welcome.

If it helps, the way I always think of it is like this:

25% combination

Apple has mutation one as EF
Carrot has mutation one as XF

If Apple contributes E (50% chance), Carrot could contribute X (50% chance) or F (50% chance)
This gives two different options:
EX and EF

Given there's a 50% chance Apple will contribute E and a 50% chance of Carrot contributing X, the calculation would be 0.5 x 0.5 = 0.25 = 25% chance of EX combination
Given there's a 50% chance Apple will contribute E and a 50% chance of Carrot contributing F, the calculation would be 0.5 x 0.5 = 0.25 = 25% chance of EF combination

Alternatively, Apple could contribute F (50% chance) and, as above, Carrot could contribute X (50% chance) or F (50% chance)
This gives two different options:
FX and FF

Given there's a 50% chance Apple will contribute F and a 50% of Carrot contributing X, the calculation would be 0.5 x 0.5 = 0.25 = 25% chance of FX combination
Given there's a 50% chance Apple will contribute F and a 50% of Carrot contributing F, the calculation would be 0.5 x 0.5 = 0.25 = 25% chance of FF combination

As a check and balance 4 combinations at 25% chance each 0.25 + 0.25 + 0.25 + 0.25 = 1
The total of the combinations should always equal 1

50% combination

Durian has mutation two as AE
Feijoa has mutation two as EE

If Durian contributes A (50% chance), Feijoa will contribute E (100% chance given that Feijoa is pure EE)
This gives one option:
AE

Given there's a 50% chance Durian will contribute A and a 100% chance of Feijoa contributing E, the calculation would be 0.5 x 1 = 0.5 = 50% chance of AE combination

Alternatively, Durian could contribute E (50% chance) and, as above, Feijoa will contribute E (100% chance given that Feijoa is pure EE)
This gives one option:
EE

Given there's a 50% chance Durian will contribute E and a 100% chance of Feijoa contributing E, the calculation would be 0.5 x 1 = 0.5 = 50% chance of EE combination

As a check and balance 2 combinations at 50% chance each 0.5 + 0.5 = 1
The total of the combinations should always equal 1

dunno if it's needed now, but we answered an FAQ about Hiddens (and their inheritance) a bit ago here